The perimeter of a triangle formed by the points (0,0),(1,0) and (0,1) is
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Let A(0,0),B(1,0),C(0,1)
Perimeter = AB+BC+CA
AB=1 unit BC=root 2 units CA=1 unit
Perimeter= 1+1+root 2 =2+root 2 units
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Perimeter = AB+BC+CA
AB=1 unit BC=root 2 units CA=1 unit
Perimeter= 1+1+root 2 =2+root 2 units
Hope it helps...
Please mark my answer as the brainliest...
Answered by
3
The points of the triangle are: A(0,0), B(1,0) and C(0,1)
Now AB = √{(1 - 0)2 +(0 - 0)2 }
=> AB = 1
BC = √{(0 - 1)2 + (1 - 0)2 }
=> BC = √{1 + 1}
=> BC = √2
CA = √{(0 - 0)2 +(1 - 0)2 }
=> CA = 1
Now perimeter of the triangle = AB +BC +CA = 1 + √2 + 1
= 2 + √2
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