Question

the perimeter of a triangle is 6p^2-4p+9 and two of its sides are p^2-2p+1 and 3p^2-5p+3. find the side of the triangle

Answer 1

let the sides are a, b and c
perimeter =a+b+c =6p²-4p+9----(1)
a=p²-2p+1---(2)
b= 3p²-5p+3---(3)

third side = c= (1) -(2)-(3)
= 6p²-4p+9 -(p²-2p+1) -(3p²-5p+3)
= 6p²-4p+9 -p²+2p-1-3p²+5p-3
=6p²-p²-3p²-4p+2p+5p+9-1-3
=2p²+3p+5