the perimeter of a triangle is 8+13a+7a^2and two of its sides are2a^2+3a+2and3a^2-4a-1.find the third side of the triangle
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Perimeter of a triangle = 8 + 13a + 7a^2
Two sides are 2a^2 + 3a + 2 & 3a^2 - 4a - 1
We know that
Third side be x.
Perimeter of triangle = sum of all three sides
7a^2 + 13a + 8 = 2a^2 + 3a + 2 + 3a^2 - 4a - 1 + x
》7a^2 + 13a + 8 = 5a^2 - a + 1 + x
》x = ( 7a^2 + 13a + 8 ) - ( 5a^2 - a + 1 )
》x = 7a^2 + 13a + 8 - 5a^2 + a - 1
》x = 2a^2 + 14a + 7
So the third side is ( 2a^2 + 14a + 7 )
Hope It helps you ..!!
✌
Perimeter of a triangle = 8 + 13a + 7a^2
Two sides are 2a^2 + 3a + 2 & 3a^2 - 4a - 1
We know that
Third side be x.
Perimeter of triangle = sum of all three sides
7a^2 + 13a + 8 = 2a^2 + 3a + 2 + 3a^2 - 4a - 1 + x
》7a^2 + 13a + 8 = 5a^2 - a + 1 + x
》x = ( 7a^2 + 13a + 8 ) - ( 5a^2 - a + 1 )
》x = 7a^2 + 13a + 8 - 5a^2 + a - 1
》x = 2a^2 + 14a + 7
So the third side is ( 2a^2 + 14a + 7 )
Hope It helps you ..!!
✌
Answered by
0
Answer:
Perimeter of a triangle = 8 + 13a + 7a^2
Two sides are 2a^2 + 3a + 2 & 3a^2 - 4a - 1
We know that third side be x.
Perimeter of triangle = sum of all three sides
7a^2 + 13a + 8 = 2a^2 + 3a + 2 + 3a^2 - 4a - 1 + x
7a^2 + 13a + 8 = 5a^2 - a + 1 + x
x = ( 7a^2 + 13a + 8 ) - ( 5a^2 - a + 1 )
x = 7a^2 + 13a + 8 - 5a^2 + a - 1
x = 2a^2 + 14a + 7
So the third side is ( 2a^2 + 14a + 7 )
Step-by-step explanation:
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