Question

the perimeter of a triangle is 8+13a+7a^2and two of its sides are2a^2+3a+2and3a^2-4a-1.find the third side of the triangle

Answer 1

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Perimeter of a triangle = 8 + 13a + 7a^2

Two sides are 2a^2 + 3a + 2 & 3a^2 - 4a - 1

We know that

Third side be x.

Perimeter of triangle = sum of all three sides

7a^2 + 13a + 8 = 2a^2 + 3a + 2 + 3a^2 - 4a - 1 + x

》7a^2 + 13a + 8 = 5a^2 - a + 1 + x

》x = ( 7a^2 + 13a + 8 ) - ( 5a^2 - a + 1 )

》x = 7a^2 + 13a + 8 - 5a^2 + a - 1

》x = 2a^2 + 14a + 7

So the third side is ( 2a^2 + 14a + 7 )

Hope It helps you ..!!

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Answer 2

Answer:

Perimeter of a triangle = 8 + 13a + 7a^2

Two sides are 2a^2 + 3a + 2 & 3a^2 - 4a - 1

We know that third side be x.

Perimeter of triangle = sum of all three sides

7a^2 + 13a + 8 = 2a^2 + 3a + 2 + 3a^2 - 4a - 1 + x

7a^2 + 13a + 8 = 5a^2 - a + 1 + x

x = ( 7a^2 + 13a + 8 ) - ( 5a^2 - a + 1 )

x = 7a^2 + 13a + 8 - 5a^2 + a - 1

x = 2a^2 + 14a + 7

So the third side is ( 2a^2 + 14a + 7 )

Step-by-step explanation:

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