The perimeter of a triangular field is 540m and its sides are in the ratio 25:17:12. Find the area of the field. Also find the cost of ploughing the field at rupees 5per meter square
Answers
Answered by
8
◆●◆●◆Step by step explanation●◆●◆●
Perimeter=540meter
Perimeter ratio=25:17:12
540=25:17:12
540=25x+17 x+12x. (1)
540=54x
540/54=x
10=x
(Putting the value of x in equation number 1)
1st side=25×10=250
2nd side=17×10=170
3rd side=12×10=120
(Area refer to the attachment)
Area=28,458
1=5₹
28,458=28,458×5
28,458=1,42,290₹
◆●◆please mark it brainliest I need of it◆●◆
Perimeter=540meter
Perimeter ratio=25:17:12
540=25:17:12
540=25x+17 x+12x. (1)
540=54x
540/54=x
10=x
(Putting the value of x in equation number 1)
1st side=25×10=250
2nd side=17×10=170
3rd side=12×10=120
(Area refer to the attachment)
Area=28,458
1=5₹
28,458=28,458×5
28,458=1,42,290₹
◆●◆please mark it brainliest I need of it◆●◆
Attachments:
anuragdixit80:
you are in which standard
Similar questions