Question

The perimeter of an isoscele right anlgled triangle is 2 p cm. its area

Answer 1

Let y is length of the hypotenuse
x-length of other one side
given that
2x + y=2p
from Pythagorean theorem
y=(2)^0.5 * x

2x + sqrt(2)x =2p
x(2+sqrt(2)) =2p
x=2p/(2+sqrt(2))
=p(2-sqrt(2))
area = x^2/2
= (p^2)(6-4sqrt(2))/2
= (p^2)(3-2sqrt(2))