the perimeter of rectangle is 100m if length is decreased by 2m and breath is increased by 3 m the area is increased by 44 m sq find length and breath
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Hey mate..
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Let, the length of the rectangle be x m And the breadth of the rectangle be y m
Given,
The perimeter of the rectangle is 100m
We know,
Perimeter of the rectangle = 2 ( L + B )
Thus,
2 ( x + y ) = 100
=> x + y = 50...(1)
Also,
If the length is decreased by 2m and breath is increased by 3 m the area is increased by 44 m
We know,
Area of the rectangle = L × B
So,
( x - 2 ) ( y + 3 ) = xy + 44
=> x ( y + 3 ) - 2 ( y + 3 ) = xy + 44
=> xy + 3x - 2y - 6 = xy + 44
=> xy - xy + 3x - 2y - 6 - 44 = 0
=> 3x - 2y = 50...(2)
Now,
We multiply Eq.(1) with 2 to get,
2x + 2y = 100...(3)
Thus,
Subtracting Eq.(2) from Eq.(3) We get,
=> ( 2x + 2y ) + ( 3x - 2y ) = 100 - 50
=> 2x + 2y + 3x - 2y = 50
=> 5x = 50
=> x = 50 / 5
•°• x = 10
Putting the value of x = 10 in Eq. (1) we get,
=> 10 + y = 50
=> y = 50 - 10
•°• y = 40
The required length of the rectangle is 10m
And the required breadth of the rectangle is 40m
Hope it helps !!
========
Let, the length of the rectangle be x m And the breadth of the rectangle be y m
Given,
The perimeter of the rectangle is 100m
We know,
Perimeter of the rectangle = 2 ( L + B )
Thus,
2 ( x + y ) = 100
=> x + y = 50...(1)
Also,
If the length is decreased by 2m and breath is increased by 3 m the area is increased by 44 m
We know,
Area of the rectangle = L × B
So,
( x - 2 ) ( y + 3 ) = xy + 44
=> x ( y + 3 ) - 2 ( y + 3 ) = xy + 44
=> xy + 3x - 2y - 6 = xy + 44
=> xy - xy + 3x - 2y - 6 - 44 = 0
=> 3x - 2y = 50...(2)
Now,
We multiply Eq.(1) with 2 to get,
2x + 2y = 100...(3)
Thus,
Subtracting Eq.(2) from Eq.(3) We get,
=> ( 2x + 2y ) + ( 3x - 2y ) = 100 - 50
=> 2x + 2y + 3x - 2y = 50
=> 5x = 50
=> x = 50 / 5
•°• x = 10
Putting the value of x = 10 in Eq. (1) we get,
=> 10 + y = 50
=> y = 50 - 10
•°• y = 40
The required length of the rectangle is 10m
And the required breadth of the rectangle is 40m
Hope it helps !!
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