what will be the n factor of mn+7 in the reaction. mn+7------mn+2 + mn+4
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the factors is a enthalpy
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2Mn
2
O
7
⟶4MnO
2
+3O
2
+7 +4
Change in oxidation state of Mn =7−4=3.
So, n-factor of Mn
2
O
7
=2×3=6.
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