Math, asked by alishyadav8cca, 4 months ago

the perimeter of rectangle is 26 cm what are the dimensions if length is 3 cm more than that of the width​

Answers

Answered by Anonymous
3

Answer:

Length = 8 cm

Breadth = 5 cm

Step-by-step explanation:

Given,

Perimeter ( rectangle ) = 26 cm

Length ( l ) = 3 + Breadth ( b )

( i.e ),

l = 3 + b

l - b = 3 ------> eq 1.

Perimeter ( rectangle ),

2 ( l + b ) = 26

l + b = 26 / 2

l + b = 13 -------> eq 2.

Add eq 1 and eq 2,

l - b  = 3

l + b = 13

_______

2l + 0 = 16

2l = 16

l = 16 / 2

l = 8 cm

Substitute l = 8 in eq 2,

8 + b = 13

b = 13 - 8

b = 5 cm

Therefore,

Length = 8 cm

Breadth = 5 cm

Answered by DüllStâr
45

Question:

The perimeter of rectangle is 26 cm what are the dimensions if length is 3 cm more than that of the width.

To find:

  • Length of rectangle

  • Width of rectangle

Given:

  • Perimeter of rectangle = 26cm

  • Length of rectangle is 3cm more than the width

Explanation:

To solve such type of questions first we have to suppose something. As here it's given length is 3cm more than width.therefore we have to suppose width as x and length as x+3. And then put their values in formula of perimeter. After solving the equation , finally we will get value of x. Which means we will get value of width. And we will get value of length by adding 3 with x.

Let's do it!

Let:

  • Length of with of rectangle = x

  • Width of rectangle = x+3

Answer:

We know:

 \sf{}perimeter \: of \: rectangle = 2(length + width)

:\implies \sf{}26= 2(x  + 3+x)

 :\implies\sf{}2x + 3 =  \dfrac{26}{2}

 :\implies\sf{}2x + 3 =  \dfrac{ { \cancel{26}}^{ \: 13} }{ { \cancel{2}}^{ \: 1} }

:\implies \sf{}2x + 3 = 13

:\implies \sf{}2x = 13 - 3

:\implies \sf{}2x = 10

:\implies \sf{}x =  \dfrac{ { \cancel{10}}^{  \: \: 5} }{ { \cancel{2}}^{ \:  \: 1} }

 :\implies \star \boxed{\sf{} x = 5} \star

As we have supposed x as width

  \blue{\therefore\star \boxed{\sf{} Width= 5cm}\star}

As we have supposed x+3 as length

  \blue{\therefore\sf{} length=5+3}

 :\implies \blue{\star \boxed{\sf{} Length=8cm}\star}

And all we are done !

:D

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