the perimeter of rectangle is 40m.the length of rectangle is 4m less than 5 times its breadth.find the length of the rectangie
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Answered by
19
Perimeter=40m
Breadth =x
Length=5x-4
Perimeter=2 (l+b)
40m=2 ({5x-4}+x)
40m=2 (6x-4)
40m=12x-8
40+8=12x
48=12x
x=48/12
x=4
Breadth =4
Length=(5×4)-4
=20-4
=16
Hope this is correct
Breadth =x
Length=5x-4
Perimeter=2 (l+b)
40m=2 ({5x-4}+x)
40m=2 (6x-4)
40m=12x-8
40+8=12x
48=12x
x=48/12
x=4
Breadth =4
Length=(5×4)-4
=20-4
=16
Hope this is correct
Answered by
13
Heya ✋
Let see your answer !!!!!
Given that
Perimeter of a rectangle = 40 m
Let the breadth of a rectangle be (x) m. Then,
length = (5x - 4) m
Perimeter of a rectangle = 2(l + b)
=> 40 = 2(5x - 4 + x)
=> 40 = 2(6x - 4)
=> 40 = 12x - 8
=> 40 + 8 = 12x
=> 48 = 12x
=> x = 48/12
=> x = 4
Hence , breadth = 4 m and
length = (5 × 4 - 4) m
= (20 - 4) m
= 16 m.
Thanks :))))
Let see your answer !!!!!
Given that
Perimeter of a rectangle = 40 m
Let the breadth of a rectangle be (x) m. Then,
length = (5x - 4) m
Perimeter of a rectangle = 2(l + b)
=> 40 = 2(5x - 4 + x)
=> 40 = 2(6x - 4)
=> 40 = 12x - 8
=> 40 + 8 = 12x
=> 48 = 12x
=> x = 48/12
=> x = 4
Hence , breadth = 4 m and
length = (5 × 4 - 4) m
= (20 - 4) m
= 16 m.
Thanks :))))
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