Question

the perimeter of rectangle of length 27 cm is 64 cm find itsarea​

Answer 1

Answer:

Perimeter = 2(l+b) or 2l+2b= 64 .cm

Perimeter = 2(27)+2b = 64 .cm

Perimeter = 54 + 2b = 64 .cm

B = 5 cm

area = lb = 5*27 = 135 sq.cm

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Answer 2

Answer:

Perimeter=2(l +b)

64=2(27+b)

64=54 +2b

64-54=2b

10=2b

b=5cm {breadth=5cm}______(eq 1)

Area of rectangle = l × b

=27×5 (from eq 1)

=135cm^2

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