Question

The perimeter of the rectangle is 80 cm. The area of the rectangle is a cm2. Show that

Answer 1

Answer:

The perimeter of the rectangle is 80 cm

The area of the rectangle is a cm^2acm

2

TO SHOW :

i) x^2- 40x + a = 0x

2

−40x+a=0

SOLUTION :

From the given we have that the perimeter of the rectangle is 80 cm.

Let x be the length of the rectangle

Let y be the width of the rectangle

The formula for perimeter of rectangle is :

Perimeter=2(l+w)Perimeter=2(l+w) units

∴ Perimeter=80=2(x+y)

80=2(x+y)

Rewritting the above equation we get

2(x+y)=80

x+y=\frac{80}{2}x+y=

2

80

∴ x+y=40

⇒ y=40-x

The area of the rectangle is a cm^2acm

2

The formula for area of rectangle is :

Area=lw square units

Answer 2

Step-by-step explanation:

The perimeter of the rectangle is 80 cm. The area of the rectangle is a cm2

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