Question

The perimeter of the triangular field is 240dm.if two of its sides are 78dm and 50dm,find the length of the perpendicular on the sides of length 50dm from the opposite vertex.
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

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ANSWER

Perimeter of the triangle = 240 dm

Two sides (given) = 78 dm and 50 dm

Third side of the triangle = 240 - (78 + 50)

= 240 dm - 128 dm

= 112 dm

s = (a + b + c)/2

= (78 + 50 + 112)/2

= 240/2

s = 120 dm

Area of the triangle = √s(s - a)(s - b)(s - c)

⇒ √120 (120 - 50)(120 - 78)(120 - 112)

⇒ √120*70*42*8

⇒ √2822400

Area of the triangle = 1680 sq dm

Now,  

Area of the triangle = 1/2*base*height

Height = 2*area/base

⇒ (2*1680)/50  

⇒ 336/5

height = 67.2 dm

thank you have a nice day/night/afternoon bro and sis