Question

The perimeter of triangle is 49 cm .One side is 7cm longer than another side and 5cm shorter than third side find the side

Answer 1

HERE IS YOUR ANSWER:

STEP-BY-STEP EXPLANATION:

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let the third side be x

one side is x-7

another side is x+5

we know that perimeter of triangle is 49cm.

x+x-7+x+5=49

3x-2=49

3x=49+2

x=51/3

x=17

one side is 17cm

second side is x-7=17-7=10

third side is x+5=17+5=22.

Answer 2

Answer:

17, 10 and 22

Step-by-step explanation:

Let the sides are a , b and c. Here,

first side = a = 7 more than b = 5 less than c

  ⇒ a = 7 + b = c - 5

⇒ a - 7 = b       &     a + 5 = c

 Given,

⇒ Perimeter = 49

⇒ Sum of all sides = 49

⇒ a + ( a - 7 ) + ( a + 5 ) = 49

⇒ a + a - 7 + a + 5 = 49

⇒ 3a - 2 = 49

⇒ 3a = 49 + 2 = 51

⇒ a = 51/3 = 17

   Hence sides are :

a = 17

a = 17a - 7 = 17 - 7 = 10

a = 17a - 7 = 17 - 7 = 10a + 5 = 17 + 5 = 22