the perimeter of triangular field is 450 M and its sides are in the ratio 13 :12 : 5. find the Area of triangle
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12
perimeter = 450m
let supoose one side = 13x
and 12x and 5x
now 13x+5x+12x =450
30x = 450
x = 450/30
x = 15
now sides are
13 × 15 = 195
12×15= 180
5×15= 75
now s = 450/2
s = 225
now root under s(s-a)(s-b)(s-c)
now put the value u will get the answer
let supoose one side = 13x
and 12x and 5x
now 13x+5x+12x =450
30x = 450
x = 450/30
x = 15
now sides are
13 × 15 = 195
12×15= 180
5×15= 75
now s = 450/2
s = 225
now root under s(s-a)(s-b)(s-c)
now put the value u will get the answer
Answered by
7
HEY BUDDY..!!
HERE IS UR ANSWER...
________________________.
=> Perimeter of field is give 450 m
=> Perimeter is sum of all sides________( 1 )
Ratio of sides are 13 : 12 : 15
Let side be x ...
According to statement 1
=> 13x + 12x + 5x = 450
=> 30x = 450
=> x = 15m
So ,
=> Sides are
⏺️13 × 15 = 195 m
⏺️12 × 15 = 180 m
⏺️5 × 15 = 75 m
HOPE HELPED..
HAVE A NICE DAY..
:-)
HERE IS UR ANSWER...
________________________.
=> Perimeter of field is give 450 m
=> Perimeter is sum of all sides________( 1 )
Ratio of sides are 13 : 12 : 15
Let side be x ...
According to statement 1
=> 13x + 12x + 5x = 450
=> 30x = 450
=> x = 15m
So ,
=> Sides are
⏺️13 × 15 = 195 m
⏺️12 × 15 = 180 m
⏺️5 × 15 = 75 m
HOPE HELPED..
HAVE A NICE DAY..
:-)
bhullakashpreetsing:
thanks
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