the sum of the digits of two digit number is 12 the number obtained by interchanging its digit exceeds the given number by 18 find the number
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let the unit digit number is x
and the tenth digit number is y
number is (10y +x)
interchange number is (10x+y)
a.t.q.
x+y=12-----1
12(10y+x)=18(10x+y)
120y+12x=180x+18y
102y=112x
51y=56x
and the tenth digit number is y
number is (10y +x)
interchange number is (10x+y)
a.t.q.
x+y=12-----1
12(10y+x)=18(10x+y)
120y+12x=180x+18y
102y=112x
51y=56x
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