Question

The perimeter of two squares are 16 cm, 12 cm. The perimeter of a square whose area is

equal to the sum of the areas of first two squares would be:
​

Answer 1

Answer:

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Answer 2

Perimeter of 1st square = 4×s1 => 16

=> s1 = 4 cm

Area of 1st square = 4² => 16 cm²

Perimeter of 1st square = 4×s2 => 12

=> s2 = 3 cm

Area of 2nd square = 3² => 9 cm²

area of the square = Area of 1st square + Area of 2nd square

=> s² = 16 + 9 cm²

=> s² = 25 cm²

=> s = $\sqrt{25 cm²}$

=> s = 5 cm$\:\:\:\:\:\:$ Ans.

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