The perimeters of two similar triangles are 25cm and 15cm. If one side of first triangle is 9cm, then what is the corresponding side of the other triangle
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7
As the triangles shows that the first triangle is 25/15=5/3 times bigger than the corresponding triangle.
therefore'
5/3 of x cm = 9 cm
x cm = (9*3/5)cm

therefore'
5/3 of x cm = 9 cm
x cm = (9*3/5)cm
Answered by
2
Answer: perimeter of ratio of two similar triangles is equal to the ratio of their corresponding side
X=side
25÷15=9÷X
X=15×9÷25
X=27÷5
X=5.4cm
The corresponding side of the second triangle is 5.4cm
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