Question

the perimeters of two squares are 60 ,114 respectively .find the perimeter of another square equal in area to the sum of first two squares . No spam please . ​

Answer 1

Answer:

Perimeter of First square = 60metres

Side of First square = 60/4 = 15m

Perimeter of second square= 144m

Side of second square = 144/4 = 36m

Therefore , Area of first square

= 15² m²

= 225m²

Area of second square

= 36²m²

= 1296m²

The area of third square is Sum of area of these two squares i.e. →

225+1296 m²

= 1521 m²

Side of third square = ✓1521 m = 39m

Perimeter = 39×4= 156m

The perimeter of third square is 156m

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Answer 2

Answer:

The answer is 111.2

Step-by-step explanation:

The sides of the first two squares are 15,23.5 respectively

Areas of first two squares are 225,552.25

Area of the another square=225+552.25=777.25

Side of another square is ~27.8

Perimeter is 4x27.8=111.2