the perimetre of an isosceles triangle measures 2 cm more than its height , and the base of the triangle measures 12 cm. find the area of the triangle...
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So we have
P of isosceles = 2a + b {a=side,&b=base}
x+2 = 2x +12
Which is equal to 10
So length is 10 cm
Area = 1/2*h*b
= 1/2*8*12
= 48 sq cm
I hope it helps !!!!
P of isosceles = 2a + b {a=side,&b=base}
x+2 = 2x +12
Which is equal to 10
So length is 10 cm
Area = 1/2*h*b
= 1/2*8*12
= 48 sq cm
I hope it helps !!!!
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