Question

The period of revolution of an earth's
satellite close to the surface of earth is
60 minutes. The period of another earth's
satellite in an orbit at a distance of three
times earth's radius from its surface will
be (in minutes)
1) 90 2)90x V8 3) 270 4) 480​

Answer 1

Answer:

Distance of satellite from the center of earth is 4 times

T2αr3T2αr3

Tαr32Tαr32

Time period of second satellite will become (4)3/2(4)3/2 ie 8 times

Hence T′=8T=8×90=720minT′=8T=8×90=720min

Hence a is the correct answer.