The period of rotation of the earth so as to make any object weightless on its equator is
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i am sorry , by mistake i pressed the submit option. but your answer is 84 minutes
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Answer:84.4 min
Explanation: the Centrifugal and centripetal forces are being balanced by each other
mg= m r (omega )2
R( omega)2= 9.8
Omega =√9.8/√ 6.4 × 10^(-3)
Omega = 2π/T
T= 2π/omega
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