the perpendiculars drawn on the arms of an angle of 50° intersect each other at P as shown in the figure find the measure of angle QPR
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6
Hi
As it is a quadirateral 50+90+90+QPR=360°(sum of all the angles of a quadirateral is 360°)
So,50+90+90+QPR=360
230+QPR=360
QPR=360-230
QPR=130°
Hope it helped you
As it is a quadirateral 50+90+90+QPR=360°(sum of all the angles of a quadirateral is 360°)
So,50+90+90+QPR=360
230+QPR=360
QPR=360-230
QPR=130°
Hope it helped you
Answered by
2
hey dude
Sum of angles of a quadrilateral is 360°
B+BQP+QPR+PRB=360°
50°+90°+QPR+90°=360°
QPR+230°=360°
QPR=130°
MARK ME AS A BRAINLIST
Sum of angles of a quadrilateral is 360°
B+BQP+QPR+PRB=360°
50°+90°+QPR+90°=360°
QPR+230°=360°
QPR=130°
MARK ME AS A BRAINLIST
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