Question

The pillars of a temple are cylindrically shaped. If each pillar has a circular base of radius 20cm and height 10m, how much concrete mixture would be required to build 14 such pillars?​

Answer 1

Answer:

Total Mixture required for 14 pillar = 17.6 m^3

Answer 2

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SOLUTION:-

Radius of base of a cylinder$\tt{ = 20cm}$

Height of the cylindrical pillar $\tt{ = 10m = 1000cm}$

So,

Volume of each cylinder $\tt{ = \pi {r}^{2} h}$

$\tt{= \frac{22}{7} \times 20 \times 20 \times 1000{cm}^{3}}$

$\tt{ = \frac{8800000}{7} {cm}^{ 3} }$

$\tt{ = \frac{8.8}{7} {m}^{3} (Since \: 1000000 {cm}^{3} = 1 {m}^{3}) }$

Therefore, Volume of 14 pillars = Volume of each cylinder × 14

$\tt{ = \frac{8.8}{7} \times 14 {m}^{3} }$

$\tt \red{ = 17.6 {m}^{3} }$

$\tt \pink{So, \: 14 \: pillars \: would \: need \: 17.6 {m}^{3} of \: concrete \: mixture.}$

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