Math, asked by thakurabhishekpe2gqa, 1 year ago

The point (0,8÷3),(1,3) and (82,30) are vertices of

Answers

Answered by gauravghaunta
12
square of one side ,a^2 = { (0-1)^2 + (8/3 -3)^2  } = 10/9 =1.11

b^2 = { (82-1)^2 + (30 -3)^2  } = 7290

 c^2 =  { (82-0)^2 + (30 -8/3)^2  } =7471.11

it shows that , c^2 > a^2 + b^2

so the triangle would be acute

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