Question

The point p divides the join of (2,1) and (-3,6) in the ratio 2:3 . Does p lie on the line x-5y+15= 0

Answer 1

hope it helps you out

Answer 2

The Point P lies on the given equation.

Step-by-step explanation:

We are given the following in the question:

Point p divides the line segment joining the points (2,1) and (-3,6) in the ratio 2:3

By section formula:

$\text{If (x,y) divides the line segment in the ratio m:n}\\\\(x,y) = (\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n})$

Thus, coordinates of P can be calculated as:

$P(x,y) = (\dfrac{2(-3)+3(2)}{2+3}, \dfrac{2(6)+3(1)}{2+3})\\\\P(x,y) = (0,3)$

We are given the equation:

$x-5y+15= 0$

Putting x = 0, y = 3

$0 - 5(3) + 15 = 0$

Since, the coordinated of P satisfies the given equation, the Point P lies on the given equation.

#LearnMore

A(-3,6),B(2,1).If p divides AB in ratio 3:2 internally and the point p line 3x-8y+k=0,find 'k'?

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