the points A (4,-2),B (7,2),C (6,9), and D (-4,-6) form a parallelogram. find the length of the altitude of the parallelogram on the base AB
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Answer:
Length of the altitude of parallelogram on the base AB is 5 units.
Step-by-step explanation:
Given points A ( 4, -2) and B (7, 2)
Equation of the line AB is given by
y + 2/x - 4 = 2 + 2/7 - 4
=> y + 2/x - 4 = 4/3
=> 3y + 6 = 4x - 16
=> 4x - 3y - 22 = 0
Length of the altitude of parallelogram is same as the perpendicular
distance from either C ( 6, 9) or D(-4, -6) to the base AB
Thus, length of altitude
= | 4*6 - 3*9 - 22|/√4² + 3²
= | 24 - 27 - 22|/5
= |-25|/5
= 5 units.
Hence length of the altitude of parallelogram on the base AB is 5 units.
Hope, it helps !
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