the points of three persons A, B , C , are in collinear . Distance between the person A and C is 60√3mts
Distance between the person C and the foot of the lighthouse is
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Given : three persons A, B , C , are in collinear . Distance between the person A and C is 60√3mts
To Find : Distance between the person C and the foot of the lighthouse
Solution:
Let say foot of the lighthouse is is D
Tan 30° = DB/AB
=> 1/√3 = DB/AB
=> AB = DB√3
Tan 60° = DB/BC
=> √3 = DB/BC
=> BC = DB/√3
AB + BC = AC
=> DB√3 + DB/√3 = 60√3
=> 3DB + DB = 180
=> DB = 45
AB = 45√3
BC = 45/√3 = 15√3
.Distance between the person C and the foot of the lighthouse is = CD
Sin 60° = DB/CD => √3/2 = 45/CD
=> CD = 90/√3 = 30√3 m
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