Question

The points scored by a Kabaddi team in a series of matches are as follows:

17, 2, 7, 27, 15, 5, 14, 8, 10, 24, 48, 10, 8, 7, 18, 28

Find the mean and median of the points scored by the team.

Answer 1

Answer:

Step-by-step explanation:

Mean = Sum of observations / Number of observations

     = 248/16

      =15.5

Median= middle most value

           If n=even ,

           avg of (n/2)th and (n/2)th+1 observations

           = avg of 8th and 9th obs.

            = 8+10/2

            = 9

Answer 2

Answer:

Mean of points scored by team is $15.5$ and median is $18$ .

Step-by-step explanation:

To find : mean and median of points scored by team .

Given scores : $17, 2, 7, 27, 15, 5, 14, 8, 10, 24, 48, 10, 8, 7, 18, 28$

Solution :

• Average is the arithmetic mean also called as mean .
• It is the ratio of sum of all the numbers given in data to the total number of observations.
• Formula: $Average \ or \ mean =\frac{\text { sum of all the observations }}{\text { total of observations }}$
• Here, sum of observations $= 248$
• Total number of observations $= 16$
• Substituting values in above formula,

        $\begin{array}{r}\text { Average \ or \ mean }=\frac{248}{16} \\=15.5\end{array}$

• Median is the middle number of the the observation in a sorted, ascending or descending order.
• If first arrange given data in ascending order , i.e. from smallest to biggest number .
• Ascending order : $2,5, 7,7,8,8,10,10,14 , 15 , 17 , 18, 24 , 27 , 28 ,48$
• Number of observation is even , that is , n = 16
• Median for even set of numbers = $\frac{(\frac{n}{2} )^{th \ observation}+(\frac{n}{2} + 1)^{th \ observation} }{2}$
•                                                       $= \frac{(\frac{16}{2}) ^{th \ observation} + (\frac{16}{2}+ 1) ^{th \ observation}}{2} \\\\=\frac{(8) ^{th \ observation} +(9) ^{th \ observation} }{2}$
•                                                       $= \frac{(10 + 14)^{th \ observation} }{2} \\\\=\frac{(24)^{th \ observation} }{2} \\\\=(12)^{th \ observation} \\\\=18$

• Since , $8^{th \ observation } = 10$ ,  $9^{th \ observation } = 14$ and $12^{th \ observation } = 18$