The polynomial 2x³-7x²+8x+22 is divided by another polynomial 2x²-5x+3. What are the respective values of quotients and remainder so obtained?
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Answer:
quotient=x-1
remainder=6x+19
step by step exaplantion:
2x²-5x+3)2x³-7x²+8x+22(x-1.
(±)2x³±(-)5x²(+)+3x.
0+11x+22
(-) +5x(+)-3.
6x+19.
q=x-1
r=6x+19
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