Question

the polynomials kx³+3x²-3 and 2x³-5x +k are divided by (x-4) then leaves the same remainder in each case , then the value of k is


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Answer 1

$\huge\underbrace\mathfrak\orange{ᴀɴsᴡᴇʀ}$

We can solve the problem using the method of long division to find the two remainders.

• On division of P(x) by (x - 4), we get the remainder as (64k + 45)

• On division of Q(x) by (x - 4), we get the remainder as (k + 108)

By the given conditions,

64k + 45 = k + 108

or, 64k - k = 108 - 45

or, 63k = 63

therefore, k = 1

Answer 2

Step-by-step explanation:

We can solve the problem using the method of long division to find the two remainders.

• On division of P(x) by (x - 4), we get the remainder as (64k + 45)

• On division of Q(x) by (x - 4), we get the remainder as (k + 108)

By the given conditions,

64k + 45 = k + 108

or, 64k - k = 108 - 45

or, 63k = 63

therefore, k = 1

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