The population of a place increased to 54000 in 2003 at a rate of 5% per annum . Find the population in 2001
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Step-by-step explanation:
So we will first find find the population in 2002.
It is given that the increase in population was 54000.
So the C.I was = 54000
Formula for compound interest is :
P [ 1 + r / 100] - P = 54000
⇒ P [ 1 + 5/100] - P = 54000
⇒ P * 105 / 100 - P → 21P/20 - P = 54000
⇒ 21P - 20P / 20 = 54000 → P = 54000* 20
P in 2002 = 10, 80, 000
Now the amount is 10, 80 , 000
As it is amount the formula would change a bit.
P [ 1 + 5/ 100] = 10, 80 , 000 ⇒ 21P / 20 = 10, 80 ,000
⇒ P = 10, 80 , 000 * 20 / 21 = 10, 80 , 000 * 0.952 = 10, 28 , 160
Note : The amount is in approximation to the the nearest natural number. I have done this because the Question also had all the values approxiamted , so you may also right in approximated form.
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