Math, asked by alaxaryan2, 1 year ago

The population of a Town in the year 2012 was 132300. If the population of the town increases every year by 5% what was the population of the town in the year 2010?

Answers

Answered by sagarkumar9155210
30

Answer:


Step-by-step explanation:

Population in 2012 = 132300

% of increases=5%

132300*10/100

=13230

132300-1323=114070

Answered by prabhat1141
66
Population of the town in 2012 = p = 132300
Rate of increase of population of town every year = r% = 5%
Therefore, Population of town before n=2 years or in 2010
 =  \frac{p}{ {(1 +  \frac{r}{100}) }^{n} }  \\  =  \frac{132300}{(1 +  \frac{5}{100}  )^{2} }  \\  =  \frac{132300}{(1 +  \frac{1}{20} {)}^{2}  }  \\  =  \frac{132300}{( \frac{20 + 1}{20} {)}^{2}  }  \\  =  \frac{132300}{( \frac{21}{20}  {)}^{2} } \\   = \frac{132300}{( \frac{441}{400}) }  \\  = 132300 \times  \frac{400}{441}  \\  = 300 \times 400 \\  = 120000
Therefore, Population of town in 2010 = 120000
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