Question

The population of a town increase by 10.5% everyday if the present population is 795600 what was the population a year ago

Answer 1

Answer:

7,20,000

Step-by-step explanation:

Let , population of the town an year ago be n

It increases by every year  =  10.5%

So, the Present population = n + (10.5/100) x n

∴  n (1 + 10.5/100 ) = 795600

n = 7,20,000

Answer 2

population increase by percentage =10.5
present population=795600
one year =265days
=10.5*265=2782.5%
let population of one year ago=X
2782.5/100*x=795600
X=795600*100/2782.5=