Question

the population of a town increase by 10 % annually. If the present population is 22000, find it population a year ago.

Answer 1

Heya,

Here is your answer :-
Present population of town = 22000
Rate of increase in population annually = 10%

Let the population 1 year ago be x .

Now,
(x + 10% of x) = 22000
(x + x/10) = 22000
11x/10 = 22000
x = 22000 × 10/11
x = 20000

So,

The population 1 year ago will be 20000.

Hope my answer will be helpful to you.

Answer 2

let population a year ago = P
population now = 22000

Thus P(1 + 10/100) = 22000

P( 1 + 0.1) = 22000

P × 1.1 = 22000

P = 22000/1.1 = 20000

It's population a year ago was 20000