The population of a town increased from 175000 to 262500 in a decade. the average percent increase of population per year is?
Answers
Answer: = 50%
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Step-by-step explanation:
1. I would give you the original formular for calculating percentage increase is:
Percentage increase = Final population ÷ original price * 100
PL= 262500 ÷ 175000 * 100 = 150
Therefore the percentage increase is 150-100 = 50%
*You might be wondering why u subtract 100 from it. This next procedure which is way more understandable would explain it to you!*
2. SIMPLE CROSS MULTIPLIICATION METHODE
- 100% is normally the highest percentage in math!
- So first lets make 175000 to be equal to 100% and this is because it is the original population. so, making it equal to hundred per cent indicates there is no recent increase or decrease that this is the "normal" (Assuming that the percentage increase was given you have to add it to 100 to show that there is an increase by this percentage making it no more "Normal", Same applies to percentage decrease you subtract it from 100% to indicate that the is a decrease in the "Normal"
175000 = 100%
262500 = x
*cross multiply*
26250000 = 175000x
*Move the 175000 across the equality sign to make x the subject. Normal algebra*
= 150% (This answer shows as that there was an increase in the population by 50% away for the normal)
= 150-100 = 50%