Math, asked by dhaval8595, 11 months ago

The population of a town increases 10% and 20% respectively in two consecutive years.After the growth the present population of the town is 13200.Then what is the population of the town 2 years ago?

Answers

Answered by venupillai
4

Answer:

The population two years ago = 10,000

Step-by-step explanation:

Let P be the original population. In the first year the population increased by 10%. This means, at the end of the first year, population is:

P + 10% of P

= P + 0.1*P

= P(1 + 0.1)

= 1.1P

In the second year, population further grows by 20%. This means that at the end of the second year, population is:

1.1P + 20% of 1.1P

= 1.1P(1 + 0.2)

= 1.1P(1.2)

= (1.1)(1.2)P

= 1.32P

We are given that population at the end of the second year is 13200

=> 1.32P = 13200

=> P = 13200/1.32

=> P = 10000

Original population (two years ago) = 10,000

Similar questions