The population of a town increases 10% and 20% respectively in two consecutive years.After the growth the present population of the town is 13200.Then what is the population of the town 2 years ago?
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Answer:
The population two years ago = 10,000
Step-by-step explanation:
Let P be the original population. In the first year the population increased by 10%. This means, at the end of the first year, population is:
P + 10% of P
= P + 0.1*P
= P(1 + 0.1)
= 1.1P
In the second year, population further grows by 20%. This means that at the end of the second year, population is:
1.1P + 20% of 1.1P
= 1.1P(1 + 0.2)
= 1.1P(1.2)
= (1.1)(1.2)P
= 1.32P
We are given that population at the end of the second year is 13200
=> 1.32P = 13200
=> P = 13200/1.32
=> P = 10000
Original population (two years ago) = 10,000
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