The population of a town is 80,000. If the rate of growth of population of the town is 4% per year, estimate the population of the town at the end of two years.
Answers
Answer:
the population of a town is 80000
rate 4%
year(t)=2 year
80000*104/100*104/100=86528
the population of the town end of two year is 86528
Concept:
Compound Interest:
It is the method in which the amount on which the interest is applied always keep on changing with each year.
Given:
We are given that:
Population = Principal Amount
= P = 80,000
Rate of growth = r = 4 %
Time = n = 2 years
Find:
the population of the town at the end of two years.
Solution:
The formula for calculating the amount after compound interest is:
Amount = P( 1 + R / 100)ⁿ
Substituting the values, we get that:
Population = 80,000( 1 + 4 / 100)²
Solving further, we get that:
Population = 80,000( 1.04 )²
Population = 80,000( 1.0816)
Population = 86,528
Therefore, the population of the town at the end of two years will be 86,528.
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