Question

. The population of a town is 80000 . The birth rate is 6 % p.a and death rate is 2 % p.a . The population of the town after 2 years is​

Answer 1

Answer:

☆ Given,

》》The population of the town

☆ To Find,

》》Population after 2 years

☆ Solution:

Annual growth = 6% - 2% = 4%

☆☆Let the population be P and Rate be R☆☆

ACQ,

》》P(1 + R/100)^n [n = population after number of years]

》》80000(1 + 4/100) ^2

》》80000(1 + 1/25)^2 [1/25 = 4/100 { Lowest Form}]

》》80000(26/25)^2 [1 + 1/25 = 26/25]

》》80000 × 26/25 × 26/25 [26/25^2 is also written as 26/25 × 26/25

》》5408000÷625

》》86528

☆Clearly,

The population of the town after two years is 86526.