Question

The position of a partical moving in a straight line is given by X=3+4T+3T2wjere x is in metre and time is in second.find the value of the following physical quantities for the particle at t=2s.

Answer 1

At t=2sec, (2) = 3 + 4(2) + 3(2) 2 = 23m
At t=0 sec,x(0)=3m
On substracting ,
x(2)-x(0),
y = x(2) − x(0) = 23 − 3 = 20m
On integrating the equation equation, v= 4 + 6t
At t=2 sec,
v(2) = 4 + 6(2) = 16
a= 3 m /s^2 .