Physics, asked by Sunilkuhar35931, 1 year ago

The position x of a particle moving along x-axis varies with time as x=4t-2t^2 the rate of change of position with time is zero at

Answers

Answered by max20
1
v = dx/ dt= 4- 4t
v=0 => t=1 sec

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Answered by rishi7586
0
Means v = 0
Here v = dx/dt = d (4t - 2t^2) 7dt = 4 - 4t =0
t = 1 second
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