The potential at a point situated at a distance of 50 cm from a charge of 5 micro Coulomb is what?
Answers
Answered by
5
f=k(5*10^-6)/(50*10^-2) N
mehreenjabeen19:
But its answer is 9×10⁴ volts how?
Answered by
1
Answer:
Just put the values in the relation V=kq/r
Attachments:
Similar questions
Environmental Sciences,
8 months ago
Physics,
8 months ago
India Languages,
1 year ago
Physics,
1 year ago