Physics, asked by poonam3066, 1 year ago

the potential difference between the terminals of a cell is found to be 3 volts when it is connected to a resistance of value equal to its internal resistance. the emf of the cell is

Answers

Answered by amitnrw
45

The potential difference between the terminals of a cell is found to be 3 volts when it is connected to a resistance of value equal to its internal resistance. the emf of the cell is

V = E - IRint

E = Emf of the cell

V = Potential Difference between terminal of cells

Rint = Internal Resistance of Battery

I = E/(Rint + Rext)

I + current flowing through circuit

Rext = Connected Resistance

Rint = Rext = R

I = E/(R + R)

I = E/2R

V = E - IR

=>V = E - (E/2R) R

=>V = E - E/2

=>V = E/2

V = 3 Volts

=> 3 = E/2

=> E = 6 V

Emf of the cell = 6 V

Answered by anshuraj6541
0

Explanation:

Correct answer will be 6V

Attachments:
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