Question

The power of a heating coil is P. it is cut into two equal parts. The power of one of them across same mains is

Answer 1

Answer: hope this will help u

Explanation:

2P

3P

`(P)/(2)`

`4P`

Solution :

`P=(V^(2))/(R),R=(rhol)/(A)`

Answer 2

Answer: 2p

Explanation: p=v^2/R

R is directly propotional to L

L'=l/2

R'=R/2

R=rhoL/A

P'=v^2/R'

V^2/R/2

2v^2/R

=2p

I guess ths helps u guys......