Question

the Prapability of a family having 4 girls (a) 9/20 (b) 7/20 (c) 11/20 (d) 13/20​

Answer 1

Answer:

girls ii. 1 girl iii. No girl

Also check whether the sum of these probabilities is 1.

Answer:

Total number of families = 475 + 814 + 211 = 1500

P(Probability of 2 girls) = No. of family having 2 girls/total no. of girls

= 475/1500

P(Probability of 1 girl) = No. of family having 1 girl/total no. of girls

= 814/1500

iii. P(Probability of No girl) = No. of family having no girl/total no. of girls

= 211/1500

Sum of all Probabilities = P(Probability of 2 girls) + P(Probability of 1 girl) + P(Probability of No

girl)

= 475/1500 + 814/1500 + 211/1500

= (475 + 814 + 211)/1500

= 1500/1500

= 1

Hence, the sum of these probabilities is 1.