Question

the present age of a father exceeds that of his son by 30 years. ten years ago the age of the father was five times that of his son. find the present age of the son​

Answer 1

Answer:

Let the present age of father be x years. and that of son be y years

10 years ago the age of the father was 5 times that of the son.

∴ x−10=5(y−10)

∴ x−5y=−40 ...(1)

20 years hence, the age of the father will be twice that of the son.

∴ x+20=2(y+20)

∴ x−2y=20 ...(2)

Subtracting (1) and (2) we get ,

y=20 and x=60

∴ The present age of father is 60 years

Step-by-step explanation:

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