Question

The present age of father is X years and son is Y years. after 3 years age of father is double the age of his son . Represent the given condition in linear equation in two variable​

Answer 1

Answer:

Let the son's age be x

Then , according to the condition,

father's age =3x+3

3 years later:

Son's age =x+3

Father's age =3x+3+3=3x+6

According to the condition given ,

3x+6=10+2(x+3)

3x+6=10+2x+6

x=10

Thus , the son's present age is 10 years and the father's age is

3x+3=3×10+3=33 years.

Step-by-step explanation:

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Answer 2

Answer:

present age of father - x years

present age of son -y years

5 years ago, Age of father was -(x-5) years, Age of son was- (y-5) years. Now according to the question. =(x-5)=7(y-5)+2,,. =x-5=7y-35+2,.. =x-7y-5+35-2°0. =x-7y+28=0