Question

the present ages of a and b are in the ratio 9:4 seven years hence ,the ratio of their ages will be 5:3.find their present age

Answer 1

Step-by-step explanation:

not sure about the amswer

Answer 2

$\Huge\bigstar\:\tt\underline\red{:ANSWER:}$

$\huge\mathscr\orange{:Let:}$

${\implies}$Present age of A is$\red{\tt{9x}}$ and B is $\purple{\tt{4x}}$

$\huge\mathscr\pink{:By problem:}$

${\implies}$After seven years A's age is =${9x+7}$

${\implies}$After seven years B's age is = ${4x+7}$

${\implies}$$\frac{9x+7}{4x+7}$=$\frac{5}{3}$

$\large\mathscr\red{:By Cross Multiplication:}$

${\implies}$${5(4x+7)=3(9x+7)}$.

${\implies}$${20x+35=27x+21}$.

${\implies}$${20x-27x=21+35}$.

${\implies}$$\cancel{-}$${7x=}$$\cancel{-}$${14}$.

${\implies}$${7x=14}$

${\implies}$${x=\frac{14}{7}}$

${\implies}$$\therefore{x=2}$.

$\therefore$ present age of A = ${9x=9×2=18}$

$\therefore$present age of B =${4x=4×2=8}$.