Question

The present ages of a father and his daughter is x years and y heard respectively.Three years Hence father will be three times as old as his daughter.7years ago he was seven times as old as his daughter.Find their present ages?

Answer 1

Answer:

Step-by-step explanation:

Let their present ages be x and y

After three years their ages will be x + 3 and y + 3 respectively

( y + 3 ) = 3 ( x + 3 )

3 x - y + 6 = 0  ....(eqn 1)

Seven years ago, their ages were x - 7 and y - 7 respectively

( y - 7) = 7 ( x - 7)

Sub eqn 1

3 x - 1  = 7 x - 49

x = 12

y = 42

Hope it Helps