The pressure of gas in a pipeline is measured with a mercury manometer having one limb open to the atmosphere. If the difference in the height of mercury in the two limbs is 562 mm, calculate the gas pressure. The barometer reads 761 mm Hg, the acceleration due to gravity is 9.79 m/s2, and the density of mercury is 13640 kg/m3
Answers
Answer:
The pressure of a gas in a pipeline is measured with a mercury manometer having one limb open. The difference in the level of the two limbs is 562mm. Calculate the gas pressure in terms of bar.Read more on Sarthaks.com - https://www.sarthaks.com/491545/the-pressure-of-gas-in-a-pipeline-is-measured-with-a-mercury-manometer-having-one-limb-open
Explanation:
The difference in the level of the two limbs = Pgauge Pgauge = Pabs – Patm Pabs – Patm = 562mm of Hg Pabs – 101.39 = ρgh = 13.6 × 103 × 9.81 × 562/1000 = 75.2 × 103 N/m2 = 75.2KPa Pabs = 101.39 + 75.2 = 176.5kPa ANS: P = 176.5kPaRead more on Sarthaks.com - https://www.sarthaks.com/491545/the-pressure-of-gas-in-a-pipeline-is-measured-with-a-mercury-manometer-having-one-limb-open
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Explanation:
The difference in the level of the two limbs = Pgauge Pgauge = Pabs – Patm Pabs – Patm = 562mm of Hg Pabs – 101.39 = ρgh = 13.6 × 103 × 9.81 × 562/1000 = 75.2 × 103 N/m2 = 75.2KPa Pabs = 101.39 + 75.2 = 176.5kPa ANS: P = 176.5k.