Question

the price of 3 chairs and 2 tables is rs 4500. the price of 5 chairs and 3 tables is rs7000 find the price of 2 chairs and 2tables ​

Answer 1

Answer:

Step-by-step explanation:

Let the cost of a chair be x.

Let the cost of a table be y.

Given that 3 chairs and 2 tables cost 700 rupees 

 3x + 2y = 700  ------ (1)

Given that 5 chairs and 3 tables cost 1100 rupees.

5x + 3y = 1100  ------ (2)

On solving (1)*3 and (2)*2, we get

10x + 6y = 2200

9x + 6y =  2100

----------------------

x = 100.

Substitute x = 100 in (1), we get

3x + 2y = 700

3(100) + 2y = 700

300 + 2y = 700

2y = 700 - 300

2y = 400

y = 400/2

y = 200.

Therefore the cost of 2 chairs = 2 * 100

                                                  = 200 rupees.

Therefore the cost of 2 tables = 2 * 200

                                                  = 400 rupees.

Verification:

3x + 2y = 700

3(100) + 2(200) = 700

300 + 400 = 700

700 = 700.

5x + 3y = 1100

5(100) + 3(200) = 1100

500 + 600 = 1100

1100 = 1100.

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Answer 2

let x be the no of chair and y be the no of tables.

3x +2y =4500 ----(1)

5x+ 3y= 7000 -----(2)

solve both the equations,we get

x =rs 500

y= rs 1500

so,

price of 2 chairs (2x) =2×500 =rs1000

price of 2 tables(2y)= 2×1500=rs3000